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2x^2-72x+640=0
a = 2; b = -72; c = +640;
Δ = b2-4ac
Δ = -722-4·2·640
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-8}{2*2}=\frac{64}{4} =16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+8}{2*2}=\frac{80}{4} =20 $
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